sql server
I''m having a similar issue to The current transaction cannot be committed and cannot support operations that write to the log file, but I have a follow-up question. The answer there
What does a transaction around a single statement do?
BEGIN TRANSACTION / COMMIT "extends" this locking functionality to the work done by multiple statements, but it adds nothing to single statements. However, the database transaction log is
Getting "Lock wait timeout exceeded; try restarting transaction" even
mysql> update customer set account_import_id = 1; ERROR 1205 (HY000): Lock wait timeout exceeded; try restarting transaction I''m not using a transaction, so why would I be getting this error? I
The transaction log for the database is full
I have a long running process that holds open a transaction for the full duration. I have no control over the way this is executed. Because a transaction is held open for the full duration, whe...
Row was updated or deleted by another transaction (or unsaved-value
optimistic locking consists in detecting that another transaction has updated/deleted the same row, and throwing the exception you''re getting in this case. If you have a version field, you''re already using
concurrency
A transaction is a unit of work that you want to treat as "a whole." It has to either happen in full or not at all. A classical example is transferring money from one bank account to another. To
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WITH (NOLOCK) vs SET TRANSACTION ISOLATION LEVEL READ
12 You cannot use Set Transaction Isolation Level Read Uncommitted in a View (you can only have one script in there in fact), so you would have to use (nolock) if dirty rows should be included.
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How do you clear the SQL Server transaction log?
The transaction log contains a lot of useful data that can be read using a third-party transaction log reader (it can be read manually but with extreme effort though). The transaction log is
"This SqlTransaction has completed; it is no longer usable
{ return transaction nnection.Query<T>(command, new DynamicParameters(param), transaction, commandType: CommandType.StoredProcedure); } } } It looks as though the outer
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